[LeetCode]--303. Range Sum Query - Immutable
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sum...
LeetCode 307 Range Sum Query - Mutable（范围和查询-可变）
版权声明：转载请联系本人，感谢配合！本站地址：http://blog.csdn.net/nomasp https://blog.csdn.net/NoMasp/article/details/51782135 翻译 给定一个整型数组nums，找出在索引i到j之间的元素的和（i <= j），包括i 和...
LeetCode - 34. Search for a Range
34. Search for a Range Problem's Link ---------------------------------------------------------------------------- Mean: 给定一个有序数组和一个数k，求k在这个数组中的起始下标和结束下标. analyse: 二分查找. ...
LeetCode 34 Search for a Range（搜索范围）
翻译 给定一个整型已排序数组，找到一个给定值在其中的起点与终点。 你的算法复杂度必须低于O(logn)。 如果目标在数组中不会被发现，返回[-1, -1]。 例如，给定[5, 7, 7, 8, 8, 10]，目标值为8，返回[3, 4]。 原文 Given a sorted array of integers, find the starting and ending ...
[LeetCode] Range Sum Query - Mutable
This problem requires a new data structure --- Segment Tree. You may use this GeeksforGeeks article to get some ideas of it. However, the code in this article may be too verbose. To solve this proble....
[LeetCode] Range Sum Query 2D - Immutable
Very similar to Range Sum Query - Immutable, but we now need to compute a 2d accunulated-sum. In fact, if you work in computer vision, you may know a name for such an array --- Integral Image. To sol....
[LeetCode] Search for a Range
The idea is to search for the left and right boundaries of target via two binary searches. Well, some tricks may be needed. Take a look at this link :-) The code is rewritten as follows. 1 class So...
[LeetCode]34.Search for a Range
【题目】 Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is n...
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