LeetCode 47. Permutations II
DescriptionGiven a collection of numbers that might contain duplicates, return all possible unique permutations.Example:Input: [1,1,2]Output:[[1,1,2],[1,2,1],[2,1,1]]描述给定一组可能有重复元素不同的整数，返回所有可能的排列（不能包含....
LeetCode 46. Permutations
DescriptionGiven a collection of distinct integers, return all possible permutations.Example:Input: [1,2,3]Output:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]描述给定一组不同的整数，返回所有可能的排列。思路递归写好递归函数的要点是....
[LeetCode] Permutations 全排列
Given a collection of numbers, return all possible permutations. For example,[1,2,3] have the following permutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], and [3,2...
[LeetCode] Permutations II 全排列之二
Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2...
leetCode 46. Permutations 回溯问题 | Medium
46. Permutations（全排列问题--回溯问题经典） Given a collection of distinct numbers, return all possible permutations. For example,[1,2,3] have the following permutations: [ [1,2,3], &nb...
[LeetCode]--47. Permutations II
Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example, [1,1,2] have the following unique permutations: [ [1,1,2], [1,2,1], [2,1,1]...
[LeetCode]--46. Permutations
Given a collection of distinct numbers, return all possible permutations. For example, [1,2,3] have the following permutations: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ]...
LeetCode - 47. Permutations II
47. Permutations II Problem's Link ---------------------------------------------------------------------------- Mean: 给定一个数组（元素可能重复），求这个数组的全排列. analyse: 注意需要先排序，和上一题的区别在于当发现要交...
LeetCode - 46. Permutations
46. Permutations Problem's Link ---------------------------------------------------------------------------- Mean: 给定一个数组，求这个数组的全排列. analyse: 方法1：调用自带函数next_permutation(_BIter...
[LeetCode] Permutations II
Well, have you solved the nextPermutation problem? If so and you have handled the cases of duplicates at that problem, your code can be used in this problem. The idea is fairly simple: sort&...
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