LeetCode 51. N-Queens
DescriptionThe n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other.Given an integer n, return all distinct solutions to the n-queens puzz....
leetcode第一刷_N-Queens II
这个题好无趣，竟然输出解的个数。前一个题把全部解都输出出来了。还愁不知道解的个数吗。 。 我怀疑这个解的个数是有一个类似通项的东西，就上网查了一下。没有啊亲，最后就把上一题的代码略微改了一下过掉了。 class Solution { public: int totalNQueens(int n) { if(n == 0) return 0; int...
[LeetCode] N-Queens N皇后问题
The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct solutions t...
[LeetCode] N-Queens II N皇后问题之二
Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. 这道题是之前那道 N-Queens N皇后问题 的延伸，说是延伸其实我觉得两者顺序应该颠倒一样，上一道题比这道题还要稍稍复杂一些，...
leetCode 51. N-Queens | 回溯问题(N皇后问题) | hard
51. N-Queens The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinc...
LeetCode:N-Queens I II（n皇后问题）
N-Queens The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct so...
LeetCode - 52. N-Queens II
52. N-Queens II Problem's Link ---------------------------------------------------------------------------- Mean: 略. analyse: 略 Time complexity: O(N) v...
LeetCode - 51. N-Queens
51. N-Queens Problem's Link ---------------------------------------------------------------------------- Mean: N-Queen问题. analyse: dfs基本功. Time complexity: O(N) ...
[LeetCode] N-Queens II
If you have solved the N-Queens problem, this one can be solved in a similar manner. Starting from the first row, we try each of its columns. If there is no attack, we move on to the next row based p....
[LeetCode] N-Queens
The idea is to use backtracking. In fact, the code below uses DFS, which involves backtracking in a recursive manner. The idea is also very simple. Starting from the first row, try each column. If it....
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